The sum of all the exterior angle of a quadrilateral taken in an order is ........
(a)90°
(b)180°
(c)360°
(d)720°
Answers
Answered by
7
There’s no way to tell unless you assume that the quadrilateral is convex.
In that case, the sum of the exterior angles, taken one at each vertex, is 360 degrees.
In that case, the sum of the exterior angles, taken one at each vertex, is 360 degrees.
Answered by
15
we use a formula
measure of each exterior angle =360/n
so this implies that the sum of all exterior angles =360
we can also prove it in a long way
measure of each exterior angle =360/n
so this implies that the sum of all exterior angles =360
we can also prove it in a long way
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Similar questions
The sum of an interior angle and exterior angle per vertex is 360.
Therefore, the sum of exterior angles for a polygon with ’n’ vertices is
= 360*n-(n-2)*180
= 180*n+360
For a quadilateral (n=4) this will be equal to 180*4+360 = 1080 degrees