Question

The sum of all those integers between 100&800 each of which divisible by 16 and leaves remainder 7

Answer 1

Best answer
answer = 19668
N = 16 + 7 (K : integer )
N = 100=>K =93 /16 =5.81=>K=6=>N=16*6+7=1003
N=800=>K =793 /16=49.56=>K=49 =>N 16*45+7=791
from 6 / includeded to 49 (included :total no. =411 it is an arithmetic progression and the sum = (103 + 791 ) *44/2 = 894 " 22 =19668
I hope you my answer help you .