Question

The sum of all two digit numbers, which are divisible by 4 is *

1180

1170

1188

1200

​

Answer 1

Answer:

1188

Step-by-step explanation:

AP: 12, 16, 20, ............., 96

a1=12

d=a2-a1=16-12

d=4

First we find no. of terms,

96=12+(n-1)4

(96-12)/4 = n-1

84/4 = n-1

21 = n-1

n=22

now we find sum of n terms

Sn = n/2 [a1+a1+(n-1)d]

==> 22/2 [12+12+(22-1)4]

==> 11 [24+21(4)]

==> 11 [24+84]

==> 11 [108]

==> 1188