Question

The sum of an ap whose first term is -4 and last term is 146 is 7171. Find the value of n

Answer 1

Answer:

Step-by-step explanation:

S= n/2(a+l)

7171 = n/2 ( -4 + 146)

7171 = n/2 (142)

7171 = 71n

n = 7171/71 = 101

Answer 2

The value of n is 100, which means that there are 100 terms in the arithmetic progression

• An arithmetic progression (AP) is a sequence of numbers where the difference between any two consecutive terms is always the same. The sum of an AP is given by the formula S = n/2 * (a + l), where n is the number of terms, a is the first term, and l is the last term.

Given that the first term of the AP is -4 and the last term is 146, and the sum of the AP is 7171, we can substitute these values into the formula and solve for n:

S = n/2 * (-4 + 146)

7171 = n/2 * 142

n = 2 * 7171/142

n = 100

So, the value of n is 100, which means that there are 100 terms in the arithmetic progression

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