Question

¥ the sum of angular momentum, spherical nodes and angular node is
(A) VORU
h-ᏎᎢ
(B)
Voh + 3
(C)
V6h+27
271
(D)
V6h+87
271​

Answer 1

Step-by-step explanation:

Given

• Ψ 321 the sum of angular momentum, spherical nodes and angular node

• We need to find the sum of angular momentum, spherical nodes and angular node.
• So Ψ 321 will be n = 3, I = 2 and m = 1
• Now l = n – 1 = 3 – 1 = 2
• So angular momentum = h / 2π √l (l + 1)
•  = h / 2 π √2 (3)
• So we get angular momentum = √6 x h / 2π  
• Now spherical nodes = n – l – 1
•   = 3 – 2 – 1
•  = 0
• Now angular nodes = l
•         = 2
• Now we need to find the sum of all three that is angular momentum + spherical nodes + angular nodes
•   = √6h / 2π + 0 + 2
•            = √6 h + 4 π / 2 π  

Reference link will be

https://brainly.in/question/13310361