Question

the sum of areas of two square is 74sq.cm .the difference between their lenghts is 2cm .find the sides of two squares.​

Answer 1

Answer:

1st square ka 7 and 2nd square ka 5

Step-by-step explanation:

this is correct answer

Answer 2

AnswEr:-

Sides of the two squares are 5cm and 7cm.

Step by Step Explanation:-

let us consider the length of the First square be x cm.

Then, The length of the second square be (x + 2) cm.

$\rule{150}2$

Now, According to Question

Sum of the Areas of the Two squares = 74 cm².

$\longrightarrow\sf\; x^2 + (x + 2)^2 = 74$

$\longrightarrow\sf\; x^2 + x^2 + 4 + 4x = 74$

$\longrightarrow\sf\; 2x^2 + 4x - 74 = 0$

$\longrightarrow\sf\; x^2 + 2x - 35 = 0$

$\longrightarrow\sf\; x^2 + 7x - 5x - 35 = 0$

$\longrightarrow\sf\; x (x + 7) -5 (x + 7) = 0$

$\longrightarrow\sf\; x = 5 \; or \; x = -7$

$\rule{150}2$

length can't be negative.

So,

$:\implies\large\boxed{\sf{\red{ x = 5cm}}}$

Length of the side of first square is 5cm.

And, length of the side of second square is 7cm.

$\rule{150}2$