the sum of denominator and numerator of a fraction is 3 less than twice the denominator if each of the numerator and denominator is denominator is decreased by when the fraction becomes upon to find the fraction
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Let the numerator and denominator be x and y respectively.
Aq
x+y=2y-3
x=2y-3-y
x=y-3 (equation 1)
But when
x-1/y-1=1/2
y-3-1/y-1=1/2
y-4/y-1=1/2
2(y-4)=1(y-1)
2y-8=y-1
2y-y=-1+8
y=7 (denominator)
x=y-3
=7-3
=4
Hence the fraction is 4/7
Aq
x+y=2y-3
x=2y-3-y
x=y-3 (equation 1)
But when
x-1/y-1=1/2
y-3-1/y-1=1/2
y-4/y-1=1/2
2(y-4)=1(y-1)
2y-8=y-1
2y-y=-1+8
y=7 (denominator)
x=y-3
=7-3
=4
Hence the fraction is 4/7
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