The sum of digit of a 2 digit number is 10. The tens digit is 4 times the ones digit. Find the number.
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hey here is your answer
Let the digit in the ten’s place be denoted by x and the digit in the unit’s place be denoted by y. The number itself is 10*x + y (for e.g. if the number is 45, 45 = 10*4 + 5).
Now we know that y = 4*x or
y - 4*x = 0 → Let’s call this Equation 1.
We also know that x+y = 10 → Let's call this Equation 2.
If we subtract Equation 1 from Equation 2, we get:
(x + y) - (y -4*x) = 10 - 0
or x + y - y -(-4*x) = 10
or
5*x = 10 or x = 2
and thus y = 4*x = 8.
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