Question

the sum of digit of a 2-digit number is 9. If 27 is subtracted from the number we get 2-digit number with the sequence of digit changed. Find the number.​

Answer 1

Answer:

63

Step-by-step explanation:

Let us assume, x and y are the two digits of the two-digit number

Therefore, the two-digit number = 10x + y  and reversed number = 10y + x

Given:

x + y = 9 -------------1

also given:

10x + y - 27 = 10y + x

9x - 9y = 27

x - y = 3 --------------2

Adding equation 1 and equation 2

2x = 12

x = 6

Therefore, y = 9 - x = 9 - 6 = 3

The two-digit number = 10x + y = 10*6 + 3 = 63

PLS MARK AS BRAINLIEST!!!!!!!

Answer 2

Let me draw an equation.

Assume Z is the Numer and it was a two digit number so,

Z = x+10y

x + y = 9

Z - 27 = 10x + y

Z = 10x + y + 27

10x + y + 27 = x + 10y

27 = x + 10y -10x -y

9y -9x = 27

9(y-x) = 27

y - x = (27/9) = 3

x + y = 9

add above two

2y = 12

y = 6

x + y = 9

x + 6 = 9

x = 3

Z = 3 + (10*6)

Z = 3 + 60 = 63

Z = 63

Hope the above equation will solve many problem by just passing different values -:-)