Question

The sum of digit of two digit number is 11 if the number obtained by reversing the digit is 9 less than the original number find the number

Answer 1

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Answer 2

Answer:

65

Step-by-step explanation:

Given:

Sum of two digit number = 11

Let unit’s digit be ‘x’

and tens digit be ‘y’,

then x+y=11…(i)

and number = x+10y

By reversing the digits,

Unit digit be ‘y’

and tens digit be ‘x’

and number =y+10x+9

Now by equating both numbers,

y+10x+9=x+10y

10x+y–10y–x=−9

9x–9y=−9

x–y=−1…(ii)

Adding (i) and (ii), we get

2x=10

x=10/2

=5

∴y=1+5=6

By substituting the vales of x and y, we get

Number = x+10y

=5+10×6

=5+60

=65

∴ The number is 65.