the sum of digit of two digit number is 9 . The new number obtained by interchanging the digits exceeds the given number by 27 . Find the given number
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Let the units digit be x
tens will be 9-x
original no.= 10×(9-x)+x
=90-10x+x
=90-9x
reversed=10x+9-x
=9x+9
90-9x+27=9x+9
117-9=18x
108=18x
6=x
original no.= 90-54
=36
tens will be 9-x
original no.= 10×(9-x)+x
=90-10x+x
=90-9x
reversed=10x+9-x
=9x+9
90-9x+27=9x+9
117-9=18x
108=18x
6=x
original no.= 90-54
=36
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