Question

the sum of digits a 2-digit number is 11. if the number obtained by reversing the digits is 9 less than the original number, find the number.

Answer 1

let the first number be x at tens place
then the second number is 11-x
original number=10x+11-x
number obtained by reversing the digits=10(11-x)+ 10x=110-10x+10x=110
ATQ,
10x+11-x+9=110
9x+20=110
x=90/9
x=10(first digit)
11-x=1(second digit)
Number =10x+11-x=100+11-10=101