The sum of digits of a 2 digit numder is 11. if 9 is added to the number its digits are reversed. find the number
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let the unit digit number=X
the ten digit number=11-x
original no.=10(11-x)+x
=110-10x+X
=110-9x
from question if 9is added then the digit are reverse.
so,110-9x+9=10(X)+11-x
or 119-9x=10x+11-x
119-9x=9x+11
-18x=-119+11
-18x=-108
X=-108/-18
X=6
so,unit digit =6
ten digit=11-6=5
so, the no.is 56
if u satisfy my answer can you please mark as brainlest bro
the ten digit number=11-x
original no.=10(11-x)+x
=110-10x+X
=110-9x
from question if 9is added then the digit are reverse.
so,110-9x+9=10(X)+11-x
or 119-9x=10x+11-x
119-9x=9x+11
-18x=-119+11
-18x=-108
X=-108/-18
X=6
so,unit digit =6
ten digit=11-6=5
so, the no.is 56
if u satisfy my answer can you please mark as brainlest bro
souravkumarin507:
i am satisfy thanks
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