Question

The sum of digits of a 2digit number is 6on. reversing it a new number is 18 less than the original number .Find the number?​

Answer 1

Answer:

Let the digit at one's place be x

The sum of the digits is 6

Let the digit at ten's place be (6-x)

Let the value of the unit digit be x*1=x

let the value of the ten's digit be (6-x)*10

=60-10

original number= 60-10x+x =60-9x

on reversing the digits = 6-x*1 + x*10

6-x+10x

6+9x

ATQ

(60-9x)-18 = 6+9x

60-18-6 = 9x+9x

36 = 18x

x = 36/18

x = 2

So, therefore the original no is

(6-x)*10 + (x)*1

(6-2)*10 + (2)*1

4*10 + 2

40 + 2

42

Reversed no =24

I HOPE THIS HELPS

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