The sum of digits of a number is 12. If both are interchanged, then the newly formed number is 36, more than the original number. What is the original number?
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Let the unit digit=X
Tens digit=12-X
The number=10(12-X)+X
The number after reversal=10(X)+12-X
The equation
10(12-X)+X-36 =10X+12-X
➡️ 120–10X+X-36=10X+12-X
➡️-10X+X-10X+X=12–120–36
➡️-18X=-144
➡️18X=144
➡️X=144/18
➡️ X=8x
X=unit digit=8
Tens digit=12–8=4
The number=10(4)+8=48
Reverse number=84
84 is 36 more than 48
So the desired number is 48
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