Question

the sum of digits of a number is subtracted from number the resulting number is always divisible by​

Answer 1

Answer:

Step-by-step explanation:

Let the number be 10x + y where x is the number in the tens place and y in the one's place.

So, 10x + y - x - y

So 9x

Since the coefficient of x is 9 the number is always divisible by 9

You can try it if you want to

Answer 2

Answer:

the sum of the digits of a number is subtracted from the number, the resulting number is always divisible by 9.

Step-by-step explanation:

Let the number be 23.

Sum of digits is 2+3=5

Now, we subtract the sum of the digits from the number itself that is 23−5=18.

18 is divisible by both 2 and 9.

Similarly, Let the number be 15.

Sum of digits is 1+5=6

Now, we subtract the sum of the digits from the number itself that is 15−6=9.

9 is divisible by 9.

Hence, the sum of the digits of a number is subtracted from the number, the resulting number is always divisible by 9.