The sum of digits of a two digit number is 10.If 18 be subtracted from it the digits in the resulting number will be equal.The Number is
Answers
Answered by
2
let the two digit number be 10x+y
sum of digits =x+y=10=>x=10-y
given,
10x+y-18=10z+z
=>10(10-y)+y-18=10z+z
=>100-10y+y-18=11z
=>82-9y=11z
=>z=82/11 - 9y/11
the single digit integer value to x and z are limited to y=3, z=5
such that x+y=10=>x=10-y=>x=10-3=7
x=7
the two digit number is 10x+y=10(7)+3=70+3=73
73-18=55
HOPE U UNDERSTAND
PLS MARK IT AS BRAINLIEST
sum of digits =x+y=10=>x=10-y
given,
10x+y-18=10z+z
=>10(10-y)+y-18=10z+z
=>100-10y+y-18=11z
=>82-9y=11z
=>z=82/11 - 9y/11
the single digit integer value to x and z are limited to y=3, z=5
such that x+y=10=>x=10-y=>x=10-3=7
x=7
the two digit number is 10x+y=10(7)+3=70+3=73
73-18=55
HOPE U UNDERSTAND
PLS MARK IT AS BRAINLIEST
nikki1231:
pls mark it as brainliest
Similar questions