Question

the sum of digits of a two -digit number is 10 the number is decreased by 36 if digit are reversed find the original number

Answer 1

Answer:

Let the first digit be 'a' and the second digit be 'b'

Therefore,

a+b=10

Now,

(10a+b) - (10b+a)=36........When a digit is in tenth place it is multiplied by 10. For e.g 64. Where 6=6×10

Hence,

9(a-b)=36

Let's add

(a+b)+(a-b)=10+4

2a=14

a=7

Therefore:

b=10-7

b=3

The number would be either 73 or 37

Answer 2

check the attachment