Question

The sum of digits of a two digit number is 11. If 9 is added to the number it's digits are reversed. Find the number​

Answer 1

Answer:

56

Step-by-step explanation:

Let the digit in the ten's place be 10x

Since the sum of the digits is 11

Hence the other digit Will be 11-x

A/Q

10x +(11-x)+9 = 10(11-x) + x

==> 10x + 11-x +9 = 110-10x+x

==> 9x+20 = 110-9x

==> 18x = 90

Hence x = 5

Therefore the no. is

10x+(11-x)

= 10×5 + (11-5)

= 50 + 6

= 56

I hope you will understand it completely

Answer 2

Answer:

let the digits be x and y and the number= 10x+y

x+y=11.....(1)

10x+y +9=10y+x

9x-9y=-9

x-y= -1......(2)

(1) + (2) gives

2x = 10

x=5

with this value of x in (2) you get y=6

So the number is 10x +y= 10×5 + 6 = 56

This is the correct method.