Question

The sum of digits of a two digit number is 11. When the digits are interchanged,
the new number formed is less than the original number by 27. Find the
original numbers.​

Answer 1

Answer:

Let the unit's place number be y and  the tenth place number be x of the two digit number  

So the number will be 10x+y

And the number formed by reversing the digits will be 10y+x

Now given, sum of digits =x+y=11

y = x + 3

11-x = x + 3

11 - 3 = 2x

8 = 2x

x = 4  

y = 11 - 4

y = 7

the total number is 47    when 27 is added it become 74

 

Hence the original number is =10x+y=10×4+7=47