the sum of digits of a two digit number is 12. if 18 is added to the number, the digits are reversed. find the original number.
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5
Answer:
57
Step-by-step explanation:
Let, the number be 10x+y
Given, x+y=12
if 18 is added to 10x+y the digits are reversed i.e, 10y+x
10x+y+18=10y+x
10y+x-10x-y=18
9y-9x=18
y-x=2
simplify the equations y+x=12 and y-x=2
Then we get y=7
substitute y=7 in x+y =12
Then we get x=5
10x+y = 10 x 5 + 7
= 50 +7 = 57
Hence, required number is 57
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