The sum of digits of a two digit number is 12. If the new number
formed by reversing the digits is greater than the original number by 54. Find the
original number.
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Answer:
original number= 39
Step-by-step explanation:
let a and b the digit
a+b=12 ........(1)
54+(10a+b)=(10b+a)
54+10a+b=10b+a
9a-9b=-54
a-b=-6........(2)
adding (1) and (2)
a+b=12
a-b=-6
----------
2a=6
a=3
so b=9
39+54=93 (verified)
orig no.=39 and No. when digits reversed=93
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