Question

The sum of digits of a two digit number is 14. If the number formed by reversing the digits is 36 more than the original number, the original number is:​

Answer 1

Let the unit digit of the original number be y.

and ten's digit be x

So Original number = 10x+y

Condition 1st:-

x+y=14---(1)

Condition 2nd:-

Number formed after reversing the digits=10y+x

$so \: 10y + x = 36 + 10x + y \\ 9y - 9x = 36 \\ y - x = 4 - - - (2)$

Adding equations 1 and 2.

2y=18

y=9

Hope it is helpful.

Answer 2

Answer:

[ Given ]

The sum of two digit = 10

Then suppose first digit = x

And second digit = y

Then the equation found x + y = 10

Now interchanging the number is decreased by 36

(10x + y) = (10y - x) -36

Then 10x - x + y - 10y = -36

9x - 9y = -36

Then all are divided by 9

So second equation found => x - y = -4

Add first and second equation

x + y = 10

+ x - y = 4

=> 2x = 6

then x = 3

Now First equation = 3 + y = 10

y = 10-3 = 7

y =7

Then original number = (10x + y)

10 x 3 + 7

=> 37 Answer √√