Question

the sum of digits of a two digit number is 15 if the new number formed by changing the places of the digit is greater than the original number by 9 find the original and also verify the solution​

Answer 1

Answer:

Here is the answer

Step-by-step explanation:

Let no be x , y

x at tens digit and y at ones digit

10x + y orginal no.

Given

x + y = 15 ---- 1 equation

A.T.Q

10 x + y = 10 y + x -9 (given on interchanging the digit the no is 9 more than original one )

so

10x - x + y - 10y = -9

9x - 9y = -9

dividing whole equation by 9

x - y = -1 -----2 equation

from equation 1 and 2

x + y = 15

x - y = -1

on adding both we get

2x = 14 so

x = 7 and y = 8

and original no was in form

10x + y = (10 × 7 + 8 )

Equals to 78

required number is 78

Answer 2

15cz+35+-& to you and (& to be a