The sum of digits of a two-digit number is 8 and the difference between the number and that formed by reversing the digit is 45 find the number
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Answered by
1
let the digits are x,y
x + y = 8
10x +y - 10y - x = 45
9x - 9y = 45
x - y = 5
x + y = 8
x + y = 8
10x +y - 10y - x = 45
9x - 9y = 45
x - y = 5
x + y = 8
Answered by
0
let two digit number be a and b first condition a + b is equal to 8 Buy second condition 10 b + a is equal to 45 by swallowing this you get correct answer
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