Question

The sum of digits of a two digit number is 8. If 36 is added to this number, the digits are
reversed. Find the number,
is four times the ones digit. When the​

Answer 1

Answer:First let the first digit x and the second digit y, so we have x+y = 8 *Equation 1* (which correlates to the sentence the sum of the digits is 8)

Second let the number z be 10x+y(for example the sum of digits of 53 is 8 however is is in fact 10(5)+3) as the question states if 36 is added the number becomes 10y+x(it switches positions, it become 10(3)+5 with reference to my last example) hence we have a second equation 10x+y+36= 10y+x

Solving it we obtain 9x-9y=-36

9y-9x= 36 *Equation 2*

Multiplying *equation 1* by 9 we have 9x+9y = 72

Adding the last two equations we have 18y= 108 so y = 6 and X = 8–6 = 2

So the number is originally 26.

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Answer 2

Answer:

The number consists of two digits in which tens digit is four times the only ones digit and the number obtained by reversing the digit is added to the original number it gives 110 find the original number

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