Question

the sum of digits of a two digit number is13. if the number is subtracted from one obtained by interchanging the digits the result is 27 whts the number plz answer and get brainlist..

Answer 1

Lets say the 2 digit number is xy

So the value of the original number is 10x + y (
If you reverse the digits then the value of the new number is 10y + x 
.. and we know that this number is 27 more than the original .. so ... 
(10y + x) = (10x + y) + 27 
Take an x away from each side 
10y = 9x + y + 27 
Take a y away from each side 
9y = 9x + 27 
.. and we can divide both sides by 9 to make it a bit simpler 
y = x + 3 
So we are looking for a 2 digit number in which one digit is 3 more than the other. 
We are also told that the sum of the digits is 13 
x + y = 13 
Since we know that y = x + 3 (from above) we can substitute for y 
x + (x + 3) = 13 
So x = 5 which means that y = 8 
Therefore the original number was 58, which when reversed becomes 85 

Hope it helps u!!

Answer 2

x+y=13
(10y+x)-(10x+y)=27
9y-9x=27
y-x=3
y=x+3
equation at the top
x+y=13
x+x+3=13
2x=10
x=5
y=8 number is 58