Question

The sum of digits of a two-digits number is 8. If 36 is added to this number, the digits are reserved.Find the number

Answer 1

Let,
x be at ten's place
& y be at unit's place

Given that x + y = 8.........(1)

Now,

10x + y + 36 = 10y + x
9x + 36 = 9y
x + 4 = y....…..………………...(2)

Solving (1) & (2) we get,
x = 2
y = 6

Required number is 26, in which adding 36 will give us 62.

Answer 26 //

Answer 2

Hey there !!

Answer:

→ 26 .

Step-by-step explanation:

Let the ten's digits of the required number be x .

And, the unit's digits be y .

Then, A/Q

∵ x + y = 8 ............(1) .

→ Required number = 10x + y .

→ Number obtained on reversing the digits = 10y + x .

⇒ 36 + 10x + y = 10y + x .

⇒ 10x - x + y - 10y = -36 .

⇒ 9x - 9y = -36 .

⇒ 9( x - y ) = -36 .

⇒ x - y = -36/9 .

∵ x - y = -4 .............(2) .

On substracting equation (1) and (2), we get

x + y = 8 .

x - y = -4 .

-    +    +

_________

⇒ 2y = 12 .

⇒ y = 12/2 .

∴ y = 6 .

On puttind the value of y in equation (1), we get

∵ x + y = 8 .

⇒ x + 6 = 8 .

⇒ x = 8 - 6 .

∴ x = 2 .

Therefore, the required number :-

= 10x + y .

= 10 × 2 + 6 .

= 20 + 6 .

= 26 .

Hence, it is solved .

THANKS

#BeBrainly .