the sum of digits of a two digits number is 9.the number obtained by reversing the order of digits is 45more than the original number. find original number?
Answers
Answer:
The Original Number is 27.
Step-by-step explanation:
Given :
Sum of the two digits of a number = 9
Number obtained by reversing = 45 more than the original number
To find :
The Original Number
Solution :
Original Number -
Let the digits be -
- Units Place as x
- Tens Place as 10(9 - x)
10(9 - x) + x
90 - 10x + x
90 - 9x ......... [Original Number]
Number with Reversed Digits -
Let the digits be -
- Units Place as (9 - x)
- Tens Place as 10(x)
10(x) + (9 - x)
10x + 9 - x
9x + 9 .......... [Number With Reversed Digits]
Number obtained by reversing = 45 more than the original number
★
The Original Number is 27.
Answer :-
Original number is 27.
Explanation :-
Let the digit at tens place be x and digit at units place be y
Sum of digits = 9
⇒ x + y = 9 --eq(1)
Number formed i.e original number = 10x + y
Number obtained when digits are reversed = 10y + x
Given
Number obtained when digits are reversed = 45 more than the original number
⇒ 10y + x = 10x + y + 45
⇒ - 45 = 10x + y - 10y - x
⇒ - 45 = 9x - 9y
⇒ - 45 = 9(x - y)
⇒ - 45/9 = x - y
⇒ - 5 = x - y
⇒ x - y = - 5 --eq(2)
Adding eq(1) and eq(2)
⇒ x + y + (x - y) = 9 + (-5)
⇒ x + y + x - y = 9 - 5
⇒ 2x = 4
⇒ x = 4/2
⇒ x = 2
Substitute x = 2 in x + y = 9
⇒ 2 + y = 9
⇒ y = 9 - 2
⇒ y = 7
Original number = 10x + y = 10(2) + 7 = 20 + 7 = 27.
∴ the original number is 27.