The sum of digits of integer number x is y. The sum of digit(s) of y is z. Find x if x+y+z= 60.
Answers
Therefore, x can be 50 or 47.
Given:
The given integer = x
The sum of digits of x = y
The sum of digits of y = z
x + y + z = 60.
To Find:
Value of x
Solution:
We can simply solve this numerical problem by using the following process.
First of all, x cannot be between 1 to 42 and 51 to 60. Because the addition of digits to make it 60 is impossible. So x should be between 43 to 50.
Here I can give two values for x.
1. x = 47
Then y = 4 + 7 = 11 and z = 1 + 1 = 2
Hence x + y + z = 47 + 11 + 2 = 60
2. x= 50
Then y = 5 + 0 = 5 and z = 5
Hence x + y + z = 50 + 5 + 5 = 60
Therefore, x can be 50 or 47.
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Answer:
The possible values of x are 47, 50
Step-by-step explanation:
Since x+y+z= 60,
we can say that 'x' is a two-digit number.
Since it is given that the sum of digit(s) of y is z, y can be a one-digit or two-digit number.
Case 1, y is a two-digit number
If y is a two-digit number,
then the value of y lies between 10 and 18 and the value of z lies between 1 and 9
Hence the minimum possible value of x is 60 - 18 - 9 = 33
and the maximum possible value of x = 60 - 10 - 1 = 49
Hence, the possible values of x are 37,38, 39, 46,47,48,49.
The value of x satisfying the given condition x+y+z= 60 is 47
Case 2, y is a single-digit number
If y is a single-digit number, then the minimum possible value of y is 1 and the maximum possible value is 9.
The minimum possible value of z is 1 and the maximum value of z is 9
Then the minimum possible value of x = 60-9-9 = 42
The maximum possible value of x = 60 -1 -1 = 58
That is the value of 'x' lies between 42 and 58
The possible value of with sum of digits are single-digit number are 42, 43, 44, 45, 50,51,52, 53, 54
The value of x satisfying the given condition x+y+z= 60 is 50.
∴The possible values of x are 47, 50
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