Question

The sum of electrons and protons present in 360ml of water at 277K

Answer 1

Answer:

360 NA

Explanation:

Calculate weight of water . since it's density is

1 cm/m3 so weight will be 360 gm .

Now calculate moles . 18 gm water is equal to 1 mol . So there are 360/18 = 20 moles .

Now there will be 20NA water molecules .

( NA is Avogadro number )

In one water molecule There are 2 Hydrogen and one oxygen . In H there is 1 proton and 1 electron . In oxygen there are 8 proton and 8 electrons .

So there are a total 18 electrons and proton in molecule .

So total electron and proton in 20 NA molecules

= 18 × 20 NA = 360 NA