Question

the sum of exterior angle of the regular polygon is 1260find the measure of each exterior angle of the polygon​

Answer 1

Answer:

We know that, Sum of measures of all interior angles of polygons =(2n−4)×90

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Given, interior angle =1260

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1260=(2n−4)×90

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1260/90=2n−4

14=2n−4

By transposing we get,

2n=14+4

2n=18

n=18/2

n=9

Therefore, the number of sides in a polygon is 9 .