the sum of father's age and twice the age of his son is 70. if we double the age of the father and add it to the age of his son the sum is 95. find their present ages
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Answered by
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Hii friend,
Let the father age be X and the age of his son be Y years.
According to question,
X+ 2Y = 70........(1)
The age of Father age get double then the age of father becomes 2X.
According to question,
2X + Y = 95........(2)
From equation 1 we get,
X + 2Y = 70
X = 70-2Y........(3)
Putting the value of X in equation (2)
2X + Y = 95
2 × (70-2Y) + Y = 95
140 - 4Y +Y = 95
140 -3Y = 95
-3Y = 95-140
-3Y = -45
Y = -45/-3 = 15
PUTTING THE VALUE OF X IN EQUATION (3)
X = 70-2Y => 70-2 × 15 = 70-30
X = 40 years
Therefore,
Age of father = X = 40 years
Age of son = Y = 15 years.
HOPE IT WILL HELP YOU..... :-)
Let the father age be X and the age of his son be Y years.
According to question,
X+ 2Y = 70........(1)
The age of Father age get double then the age of father becomes 2X.
According to question,
2X + Y = 95........(2)
From equation 1 we get,
X + 2Y = 70
X = 70-2Y........(3)
Putting the value of X in equation (2)
2X + Y = 95
2 × (70-2Y) + Y = 95
140 - 4Y +Y = 95
140 -3Y = 95
-3Y = 95-140
-3Y = -45
Y = -45/-3 = 15
PUTTING THE VALUE OF X IN EQUATION (3)
X = 70-2Y => 70-2 × 15 = 70-30
X = 40 years
Therefore,
Age of father = X = 40 years
Age of son = Y = 15 years.
HOPE IT WILL HELP YOU..... :-)
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