Question

the sum of first 10 multiple of 6 is​

Answer 1

Answer:

1. sum=6+12+18+24+30+36+42+48+54+60=330

Answer 2

Let it be an AP :- 6,12,18.....36

Sn

$\frac{n}{2} (2a + (n - 1)d)$

n=6

a=6

d=6

$sn = \frac{6}{2} (2 \times 6 + (6 + 1)6) \\ </strong><strong>=</strong><strong>3(12 + 42) \\ </strong><strong>=</strong><strong>3 \times 54 = 162$