Question

The sum of first 100 multiples​

Answer 1

Answer:

The sum of first n terms of arithmetic series formula can be written as,

S

n

=

2

n

[2a+(n−1)d]

Where n = number of terms ⇒ 100

a = first even number ⇒ 12

d = common difference of A.P. ⇒ 12

Apply the given data in the formula,

S

100

=

2

100

[2×12+(100−1)12]

=50[24+(99)12]

=50[24+1188]

=50[1212]

=60,600

So, the sum of first 100 multiples of 12 is 60600.

Answer 2

60600 is the right answer
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