Question

The sum of first 100 multiples of 8
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Answer 1

Answer:

Your answer will be 40400

Step-by-step explanation:

Using the formula for sum of An Arithmetic Progression

Formula : $\frac{n}{2}$(2a+(n-1)d)

here, n is the total number of terms

         a is the first term

        d is the difference between two consecutive terms

Answer 2

Answer :

First 100 multiples of 8 are in A.P.

8 , 16 , _ _ _ _ _ _ _ , 800

a = 8 , d = 8 , n = 100 , tn = 800

Sn = n/2 [ 2a + ( n - 1 ) × d ]

S¹⁰⁰ = 100/2 [ 2(8) + ( 100 - 1 ) × 8 ]

= 50 [ 16 + 99 × 8 ]

= 50 [ 16 + 792 ]

= 50 × 808

S¹⁰⁰ = 40400

Therefore ,

Sum of first 100 multiples of 8 are 40400.