Question

the sum of first 16 term of the AP 10, 6, 2 .... is​

Answer 1

hey mate ,

a=10

d= -4

Sn = n/2 (2a+(n-1)d)

S16 = 16/2 (2×10 + (16-1)-4)

S16 = 8(20-60)

S16= 8×-40

S16 = -320

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Answer 2

Answer:

an=a+(n-1)d

an=10+(16-1)-4

an=10-60

an=-50

S16=n/2(a+l)

s16=16/2{10+(-50)}

s16=8×(-40)

s16=-320

here is your answer.

Hope it helps you...