Question

The sum of first 16 terms of an ap is 528 and the sum of next 16 terms is 1552 find the term and common difference

Answer 1

sum of n series of an AP= (1st term+last term)*n/2
let first term be x and common difference be a
sum of 1st 16term= (x+x+(16-1)a)*16/2
                             =(2x+15a)*8=528
2x+15a=66.......(1)

sum of next 16 term=1552
(x+(17-1)a+x(32-1)a)*16/2=1552
2x+16a+31a=194
2x+47a=194.......(2)
(2)-(1)
--> 47a-15a=194-66
     32a=  128
         a=4
2x+15*4=66
2x=66-60
x=6/2
x=3

!st term = 3 and common difference =4

Answer 2

Answer:

Here is the answer

Step-by-step explanation:

MARK BRAINLIEST!!!!!