Question

the sum of first 20 terms of an aratmatice programme whose first term is 5 and co man difference is 4 is​

Answer 1

Answer:

a=5

d=4

Sum of 20 terms =n/2[2a + (n – 1)d]

=20/2[ 2×5 +(20-1)4]

=10 (10 + 76)

= 860

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

a = 5 , d = 4 , s20 = ?

sn = n/2 ( a + an  )

an = a + (n - 1 )d

an = 5 + (20 - 1) 4

an = 5 + 19 (4)

an = 5 + 76

an = 81

sn = n/2 (a + an )

s20 = 20/2 ( 5 + 81 )

s20 = 10 (86)

s20 = 860

SO THE SUM OF FIRST 20 TERMS IN AN AP WHOSE FIRST TERM IS 5 AND COMMON DIFFERENCE 4 IS 860

SPELLING MISTAKES

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*ARITHMETIC PROGRESSION

*COMMAN DIFFERENCE