Question

The sum of first 22 terms of the A.P 8,3,-2,....... is​

Answer 1

Step-by-step explanation:

The sequence given is 10, 7, 4, ....-62.

First we need to find out number of terms in this sequence.

'a' = 10, 'd' = -3, last term = -62

t

n

=a+(n−1)d

⟹−62=10+(n−1)(−3)

⟹−62=13−3n

⟹3n=75orn=25.

The number of terms in the sequence is 25.

The 11th term from the end is same as the 15th term from the first.

So, t

15

=10+(15−1)(−3)

⟹t

15

=10+(14)(−3)

⟹t

15

=−32

.

The 11th term from the end is -32.

Answer 2

s=n/2[2a+(n-1)d]

=22/2[2×8+(22-1)×-5]

=11[16+(21)×-5]

= 11[16+(-85)]

=11[-69]

-759

hence ur ans is -759

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