The sum of first 45 natural numbers is:
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HI !
An AP is formed ,
1,2,3,4 .....
a = 1 , d = 1 , n = 45
S₄₅ = n/2 [ 2a + [ n-1]d ]
= 45/2 × [ 2 + 44 ]
= 45 /2 × 46
= 1035
∴ Sum of first 45 natural numbers = 1035
An AP is formed ,
1,2,3,4 .....
a = 1 , d = 1 , n = 45
S₄₅ = n/2 [ 2a + [ n-1]d ]
= 45/2 × [ 2 + 44 ]
= 45 /2 × 46
= 1035
∴ Sum of first 45 natural numbers = 1035
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