Math, asked by numesh7605, 11 months ago

The sum of first 50 odd natural numbers is

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Answered by Anonymous
5

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sum =  \frac{n}{2} (2a + (n - 1)d) \\  \\ sum =  \frac{50}{2} (2 \times 1 + 49 \times 2 \\  \\ sum = 25 (2 + 98) \\  \\ sum = 25 \times 100 \\  \\ sum = 2500

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