the sum of first 50 term of sequence 10 20 25
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Answer:
given,
a=10, d=20-10=10 ,. n=50
therefore,
SN= n/2[2a+(n-1)d]
S50=50/2[2×10+(50-1)10]
= 25[20+49×10]
=25[20+490]
=25×510
=12750
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