The sum of first five terms of an ap and the sum of srven terms of the same ap is 167.If the sum of the first ten terms of an ap is 235 fins the sum of its twenty term
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s5+s7=167
= 5/2(2a+(5-1)d)+7/2(2a+(7-1)d)=167-----eqn.1
s10=235
10/2(2a+(10-1)d)=235
2a+9d=47---------eqn.2
solving both the eqn. we get a=1 and d=5
s20=20/2(2(1)+(19)5
=10(97)
=970
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