The sum of the ages of two friends is 20 years 4 years ago the product of stages in year was 48
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Given the sum of the ages of two friends is 20 years.
let one age = x and the other age is 20 - x
After 4 years ago,
ages are (x - 4) and (20 - x - 4) = (16 - x)
Again given product of age is 48
=> (x - 4)*(16 - x)=48
=> 16x - x2 - 64 + 4x = 48
=> -x2 + 20x -64 - 48 = 0
=> -x2 + 20x - 112 = 0
then find x and y
let one age = x and the other age is 20 - x
After 4 years ago,
ages are (x - 4) and (20 - x - 4) = (16 - x)
Again given product of age is 48
=> (x - 4)*(16 - x)=48
=> 16x - x2 - 64 + 4x = 48
=> -x2 + 20x -64 - 48 = 0
=> -x2 + 20x - 112 = 0
then find x and y
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