The sum of first four multiples of 8
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Answered by
11
8 +16+24+32=84 ......
mn121:
The question is of sum of first four multiples
Answered by
17
Hii friend....
A.p. = 8 , 16 , 24,36..
n= 4
d = 8
S4 =?
_______________________________________
Sn = n/ 2[2a+(n-1)d]
= 4/2 [ 2×8+(4-1) 8]
= 2 [ 16 +3×8]
= 2 [ 16 + 24]
= 2[40]
= 80
So sum of first 4 multiples of 8 is 80.
THANKS
HOPE IT HELPS U☆☆
A.p. = 8 , 16 , 24,36..
n= 4
d = 8
S4 =?
_______________________________________
Sn = n/ 2[2a+(n-1)d]
= 4/2 [ 2×8+(4-1) 8]
= 2 [ 16 +3×8]
= 2 [ 16 + 24]
= 2[40]
= 80
So sum of first 4 multiples of 8 is 80.
THANKS
HOPE IT HELPS U☆☆
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