The sum of first ‘n’ odd natural numbers is
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(n) square is the answer for question
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Answer:
n²
Step-by-step explanation:
The first n odd natural numbers are given by 1,3,5,7,9…… (2n – 1) and this forms an AP.
a = 1
d = 2
tn = (2n – 1)
The formula of sum of an A.P series
=>S = n/2[2a + (n − 1) × d]
=>S = n /2 [2 + 2n – 2]
=>S = n /2 [2n]
=>S = n²
The sum of first n odd natural numbers is n²
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