Math, asked by nazi74, 11 months ago

the sum of first n odd numbers be 625 then write the value of n

Answers

Answered by pradnya102

hope it will help you

Attachments:

ayushukamath041: n^2=625

ayushukamath041: n^2=625. n=√625 n=+or- 25

pradnya102: first odd numbers are positive. sum of positive numbers is never negative

pradnya102: so n=25

pradnya102: n means total quantities in a group. no of quantities is never negative.

pradnya102: we dont say there are-25 students in the class.we say that there are 25 students so n=25

pradnya102: plz mark as brainlist. as your wish

Answered by amitnrw

Step-by-step explanation:

the sum of first n odd numbers be 625

First n odd numbers

1 , 3 , 5 , ................................................2n-1

a = First Term = 1

n = n = number of terms

d = common difference = 2

last term = a + (n - 1)d = 1 + (n - 1)*2 = 2n - 1

Sum on N terms = (n/2)(first Term + Last term)

= (n/2)(1 + 2n - 1)

= (n/2)(2n)

= n²

n² = 625

=> n = 25

Value of n = 25

Learn more:

Find the sum of first n odd natural numbers. - Brainly.in

https://brainly.in/question/899893

What is the sum of first 'n' odd positive integers? - Brainly.in

https://brainly.in/question/8349491

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