Question

the sum of first n odd positive integers is : (1) n (n+1). (2) n(n+1)/2 (3) n2 (4) 2n+1 ​

Answer 1

Answer:

2n+1

Let's verify the answer :

n = 1 then 2n+1 = 2×1+1 = 3 (odd)

n = 2 then 2n+1 = 2×2+1 = 5 (odd)

Answer 2

Answer:

(3)n²

Step-by-step explanation:

1+3+5+...+(2n-1)=n²

Hope it helps you...

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