Question

The sum of first n odd positive integers is: 

n(n+1)

n(n+1)/2

n²

2n+1​

Answer 1

Answer:

n^2

Step-by-step explanation:

follow m12345780123

Answer 2

Answer:

n²

Step-by-step explanation:

odd positive integer numbers is 1,3,5,...(2n-1)

a=1 , d=3-1=2 and

an=a+(n-1)d = 1+(n-1)2 = (2n-1)

sn =n/2 (a+l)

=n/2 (1+2n-1)

=n/2 (2n)

=n(n)

sn =n²